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textbook:nrctextbook:chapter6 [2025-03-25 15:33] Merja Herzig |
textbook:nrctextbook:chapter6 [2025-05-07 12:01] (current) Merja Herzig |
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| Earlier //Curie// (Ci) was used as the activity unit. One Curie is 3.7×10< | Earlier //Curie// (Ci) was used as the activity unit. One Curie is 3.7×10< | ||
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| - | Figure VI.2. Individual and total activities of two coexisting radionuclides as a function of time. Top: activity in linear scale. Bottom: activity in logarithmic scale. Diamond (blue): Radionuclide with a half-life of 3 hours. Square (red): radionuclide with a half-life of 12 hours. Triangle (green): total activity. | + | Figure VI.2. Individual and total activities of two coexisting radionuclides as a function of time. Top: activity in linear scale. Bottom: activity in logarithmic scale. Diamond (blue): Radionuclide with a [[textbook: |
| - | * For [[textbook: | + | * For [[textbook: |
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| - | For example, when the half-life is 106 years the activity decreases by 0.00007% in one year. Small differences in activity like this cannot be measured. To determine the half-life of long-lived radionuclides we need to measure the mass (m) of the radionuclide and count rate (R) obtained from the activity measurement. In addition, we also need to accurately know the counting efficiency (E) of the measurement system. If, for example, we have 1.27 mg of < | + | For example, when the [[textbook: |
| is 51.5% (0.515) the activity of the sample is $A = \frac{R}{E} = \frac{2.65 \, \text{s}^{-1}}{0.515} = 5.15 \, \text{Bq}$. The number of thorium atoms in the sample is $1.27 \cdot 10^{-3} \, \text{g} \times \frac{6.023 \cdot 10^{23} \, \text{atoms/ | is 51.5% (0.515) the activity of the sample is $A = \frac{R}{E} = \frac{2.65 \, \text{s}^{-1}}{0.515} = 5.15 \, \text{Bq}$. The number of thorium atoms in the sample is $1.27 \cdot 10^{-3} \, \text{g} \times \frac{6.023 \cdot 10^{23} \, \text{atoms/ | ||
| Now the half-life can be calculated from the equation $t_{1/2} = \left( \frac{\ln 2}{A} \right) \times N = \frac{0.693 \times 3.295 \cdot 10^{18}}{5.15 \, \text{s}^{-1}} = 4.44 \cdot 10^{17} \, \text{s} = 1.41 \cdot 10^{10} \, \text{a}$. This method can also in principle be used to measure half-lives of shorter lived radionuclides but in their case the accurate measurement of the mass may either completely exclude the use of this method or at least results in inaccurate value. | Now the half-life can be calculated from the equation $t_{1/2} = \left( \frac{\ln 2}{A} \right) \times N = \frac{0.693 \times 3.295 \cdot 10^{18}}{5.15 \, \text{s}^{-1}} = 4.44 \cdot 10^{17} \, \text{s} = 1.41 \cdot 10^{10} \, \text{a}$. This method can also in principle be used to measure half-lives of shorter lived radionuclides but in their case the accurate measurement of the mass may either completely exclude the use of this method or at least results in inaccurate value. | ||
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| ===== 6.7. Activity equilibria of consecutive decays ===== | ===== 6.7. Activity equilibria of consecutive decays ===== | ||
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| - | In the following we discuss two consecutive decay processes and their activity equilibria. Equilibrium means that the activities of the parent and daughter nuclides are the same. Consecutive decays and their equilibria are especially important in natural decay chains of uranium and thorium and in beta decays | + | In the following we discuss two consecutive decay processes and their activity equilibria. |
| - | require computer programs. An example of such calculation is given at the end of the chapter. Here we, however, focus on equilibrium between two radionuclides, | + | |
| in turn is dependent both on its own decay rate (λ< | in turn is dependent both on its own decay rate (λ< | ||
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| The solution of this equation with respect to N< | The solution of this equation with respect to N< | ||
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| - | where // | + | where // |
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| - | * transient | + | * [[textbook: |
| - | * no-equilibrium, | + | * [[textbook: |
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| ==== 6.7.1. Secular equilibrium ==== | ==== 6.7.1. Secular equilibrium ==== | ||
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| - | An example of a secular equilibrium is case where the parent nuclide is the fission product < | + | An example of a secular equilibrium is case where the parent nuclide is the [[textbook: |
| decays following its half-life on 2.6 minutes (red). The activity of < | decays following its half-life on 2.6 minutes (red). The activity of < | ||
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| - | Secular does not mean eternal. Looking at a very long-term all secular equilibria are transient. How long-term we need to look depends on the half-life of the parent. For example, if we looked the example describe above for a hundred years period the equilibrium would appear as transient equilibrium. For < | + | Secular does not mean eternal. Looking at a very long-term all secular equilibria are [[textbook: |
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| - | Figure VI.4. Development of a secular radioactive equilibrium in which the half-life of the parent nuclide very long and the half-life on the daughter nuclide (< | + | Figure VI.4. Development of a secular radioactive equilibrium in which the half-life of the parent nuclide very long and the half-life on the daughter nuclide (< |
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| ==== 6.7.2. Transient equilibrium ==== | ==== 6.7.2. Transient equilibrium ==== | ||
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| - | An example of transient equilibrium is a beta decay chain where < | + | An example of transient equilibrium is a [[textbook: |
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| Figure VI.5. Development of a transient radioactive equilibrium in which the half-life of the parent (< | Figure VI.5. Development of a transient radioactive equilibrium in which the half-life of the parent (< | ||
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| - | The transient equilibrium is otherwise identical with the secular equilibrium except that the parent nuclide decays with such a short rate that we observe decrease in activity in a reasonable time. After attaining the equilibrium in about ten half-lives of the daughter, about two weeks in case of Fig.VI.5, both parent and the daughter decay at the rate of the parent nuclide. Also, after attaining the equilibrium the total activity is twice the activity of the parent nuclide. | + | The transient equilibrium is otherwise identical with the [[textbook: |
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| ==== 6.7.3. No-equilibrium ==== | ==== 6.7.3. No-equilibrium ==== | ||
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| - | An example of no-equilibrium case is the alpha decay pair < | + | An example of no-equilibrium case is the [[textbook: |
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| Figure VI.6. Development of activities in case of no radioactive equilibrium, | Figure VI.6. Development of activities in case of no radioactive equilibrium, | ||
| - | Left: activity on linear scale. Right: activity on logarithmic scale. Blue: < | + | Left: activity on linear scale. Right: activity on logarithmic scale. Blue: < |
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| ==== 6.7.4. Equilibria in natural decay chains ==== | ==== 6.7.4. Equilibria in natural decay chains ==== | ||
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| - | In natural uranium and thorium decay chains there are individual pairs in which there would not be any equilibrium if they were present separately. An example of such pairs in the 238U decay chain is < | + | In natural uranium and thorium |
| - | equilibrium since the grandparent of < | + | equilibrium since the grandparent of < |
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| - | In the geosphere in the natural decay chains beginning from < | + | In the geosphere in the natural |
| - | uranium-bearing mineral by oxidation the remaining radionuclides in the series will be supported by its most long-lived radionuclide which is < | + | |
| - | series, < | + | |
| - | utilized in dating geological events. If for example, the < | + | |
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| - | To calculate activities of all members in a series manually is a cumbersome task. Computer programs for this purpose have been fortunately developed. One of them is the Decservis-2 program developed at the Laboratory of Radiochemistry, | + | To calculate |
| - | 10000 years. We have to assume that the gaseous < | + | |
| - | < | + | |
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email: mst@evalion.cz | tel: +420 224 358 331 | Copyright © 2021 A-CINCH
This project has received funding from the Euratom research and training programme 2019–2020 under grant agreement No. 945301.